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can you solve this
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Thread: can you solve this
08-14-2024, 11:25 PM
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#1
- MiscMathematician
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can you solve this
+
-
= 0
+
+
= 24
-
= 4
08-14-2024, 11:34 PM
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#2
08-14-2024, 11:38 PM
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#3
- SuperHercules
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8 4 12
See Shakebrah's sig
08-14-2024, 11:40 PM
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#4
- headturner1
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- headturner1
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BRB reduced row echelon incoming
08-14-2024, 11:45 PM
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#5
08-14-2024, 11:59 PM
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#6
- MiscMathematician
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Originally Posted By SuperHercules⏩
rept on rc8 4 12
08-15-2024, 12:02 AM
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#7
- dingerberry2
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Originally Posted By tendies⏩
LoldO + P = pha g g ot
You must spread some Reputation around before giving it to tendies again.
08-15-2024, 12:06 AM
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#8
08-15-2024, 12:07 AM
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#9
- dingerberry2
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Originally Posted By hugecepts⏩
Mirin deduction skills alt brah8 4 12
tbf you have to have advanced knowledge of mathematics, string theory, cryptography, algebra, geometry, and symmetry to solve this problem so i understand why i was the first to crack this code
tbf you have to have advanced knowledge of mathematics, string theory, cryptography, algebra, geometry, and symmetry to solve this problem so i understand why i was the first to crack this code
08-15-2024, 12:08 AM
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#10
08-15-2024, 12:17 AM
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#11
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Originally Posted By headturner1⏩
would be impressed if somone reduce a matrix for this lolBRB reduced row echelon incoming
08-21-2024, 07:32 PM
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#12
- Girthquake505
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I copy and pasted this into chat gpt and within like 2 seconds it gave me the solution:
Certainly! Let's solve the system of equations given:
1. **; ) + : ( - : ) = 0**
2. **; ) + : ( + : ) = 24**
3. **; ) - : ( = 4**
Let's denote:
- **[img]//assets.bodybuilding.com/forum/images/smilies/wink.gif[/img]** as \( x \)
- **[img]//assets.bodybuilding.com/forum/images/smilies/frown.gif[/img]** as \( y \)
- **[img]//assets.bodybuilding.com/forum/images/smilies/smile.gif[/img]** as \( z \)
We can rewrite the equations as:
1. \( x + y - z = 0 \)
2. \( x + y + z = 24 \)
3. \( x - y = 4 \)
### Step-by-Step Solution:
**Step 1: Solve for \( y \) using the third equation**
From the third equation:
\[ x - y = 4 \]
Rearrange to find \( y \) :
\[ y = x - 4 \]
**Step 2: Substitute \( y = x - 4 \) into the first and second equations**
**Substitute into the first equation**:
\[ x + (x - 4) - z = 0 \]
Simplify:
\[ 2x - 4 - z = 0 \]
\[ z = 2x - 4 \]
**Substitute into the second equation**:
\[ x + (x - 4) + z = 24 \]
Substitute \( z = 2x - 4 \):
\[ x + (x - 4) + (2x - 4) = 24 \]
Combine terms:
\[ x + x - 4 + 2x - 4 = 24 \]
\[ 4x - 8 = 24 \]
Add 8 to both sides:
\[ 4x = 32 \]
Divide by 4:
\[ x = 8 \]
**Step 3: Find \( y \) and \( z \)**
Using \( x = 8 \):
\[ y = x - 4 \]
\[ y = 8 - 4 \]
\[ y = 4 \]
Using \( x = 8 \) to find \( z \):
\[ z = 2x - 4 \]
\[ z = 2(8) - 4 \]
\[ z = 16 - 4 \]
\[ z = 12 \]
### Solution
- **; )** \( x = 8 \)
- **: (** \( y = 4 \)
- **: )** \( z = 12 \)
So the values are:
- **[img]//assets.bodybuilding.com/forum/images/smilies/wink.gif[/img]= 8**
- **[img]//assets.bodybuilding.com/forum/images/smilies/frown.gif[/img]= 4**
- **[img]//assets.bodybuilding.com/forum/images/smilies/smile.gif[/img]= 12**
Certainly! Let's solve the system of equations given:
1. **; ) + : ( - : ) = 0**
2. **; ) + : ( + : ) = 24**
3. **; ) - : ( = 4**
Let's denote:
- **[img]//assets.bodybuilding.com/forum/images/smilies/wink.gif[/img]** as \( x \)
- **[img]//assets.bodybuilding.com/forum/images/smilies/frown.gif[/img]** as \( y \)
- **[img]//assets.bodybuilding.com/forum/images/smilies/smile.gif[/img]** as \( z \)
We can rewrite the equations as:
1. \( x + y - z = 0 \)
2. \( x + y + z = 24 \)
3. \( x - y = 4 \)
### Step-by-Step Solution:
**Step 1: Solve for \( y \) using the third equation**
From the third equation:
\[ x - y = 4 \]
Rearrange to find \( y \) :
\[ y = x - 4 \]
**Step 2: Substitute \( y = x - 4 \) into the first and second equations**
**Substitute into the first equation**:
\[ x + (x - 4) - z = 0 \]
Simplify:
\[ 2x - 4 - z = 0 \]
\[ z = 2x - 4 \]
**Substitute into the second equation**:
\[ x + (x - 4) + z = 24 \]
Substitute \( z = 2x - 4 \):
\[ x + (x - 4) + (2x - 4) = 24 \]
Combine terms:
\[ x + x - 4 + 2x - 4 = 24 \]
\[ 4x - 8 = 24 \]
Add 8 to both sides:
\[ 4x = 32 \]
Divide by 4:
\[ x = 8 \]
**Step 3: Find \( y \) and \( z \)**
Using \( x = 8 \):
\[ y = x - 4 \]
\[ y = 8 - 4 \]
\[ y = 4 \]
Using \( x = 8 \) to find \( z \):
\[ z = 2x - 4 \]
\[ z = 2(8) - 4 \]
\[ z = 16 - 4 \]
\[ z = 12 \]
### Solution
- **; )** \( x = 8 \)
- **: (** \( y = 4 \)
- **: )** \( z = 12 \)
So the values are:
- **[img]//assets.bodybuilding.com/forum/images/smilies/wink.gif[/img]= 8**
- **[img]//assets.bodybuilding.com/forum/images/smilies/frown.gif[/img]= 4**
- **[img]//assets.bodybuilding.com/forum/images/smilies/smile.gif[/img]= 12**
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