Log In

Your email is not your username

Register

If you were a member of the old Bodybuilding.com forums and would like to reuse your previous username, you can request it below. We use your email only for registration and do not store it. For more information, please see our Privacy Policy.

Confirm your email

A registration code was sent to your email. Enter it here.

Welcome

You have successfully setup your account.

Sign in

Quick Navigation Bottom Misc
Forum
» A Final Logic Question
  1. Results 61 to 90 of 90
  2. First
  3. 1
  4. 2
  5. 3
post 1648571063 10-08-2021, 02:21 PM
-
#61
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By l2ambo
Where was there a yes answer? lol
You are not following this. To repeat:

B could never have said A is a knave at any time in the past. B literally cannot utter true statements. Saying A is a knave would be a true statement.

The Yes answer then follows from that.
Originally Posted By l2ambo
If B once said that A is a knave. A could say no it's not true that he said it (in the past) Then log asks b whether or not a is a knave and he lies and says no. Logician 1 still has no idea that B is a knave. He could be a knight for all log 1 knows.
Your mistake is at the very beginning.B cannot have once said that A is a knave.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648571573 10-08-2021, 02:28 PM
-
#62
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Look at the question. "is it true that B once said you are a knave"? Knave A says NO. What's wrong with this answer?

If you asked B the second question first, then asked A the first question, you're assertions would be accurate but since the questions are reversed, mine are.
"Movin' ahead so life won't pass me by."
post 1648572623 10-08-2021, 02:47 PM
-
#63
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By l2ambo
Look at the question. "is it true that B once said you are a knave"? Knave A says NO. What's wrong with this answer?

If you asked B the second question first, then asked A the first question, you're assertions would be accurate but since the questions are reversed, mine are.
Not at all. This has nothing to do with the second question. What’s wrong with that first part? Knave A cant say no. As explained above.

Let’s try a different approach.

Can a knave ever say “2+2=4?”. Could he have ever said this in the past? Yes or no.
Originally Posted By Spazzzzy
Fuark got zero sleep last night but will dust off my thinking cap for this one beyond the initial high level look yesterday.

Pretty fun, havent had to use brain for anything in years tbh.
Dang not trying to cause less sleep here. I was up late responding myself, ha. Ah well, I think you guys have some good approaches in here, answer will come eventually. That or everyone just gets tired of it and I’ll give it.

Edit to I2ambo below:

Yes you are right that Log 1 No/No thing is all kind of tangent to the main problem, prob not worth going on about.

You can’t just say Log 2 was the one who deduced it though without justification. Say perhaps you find a combo such that Log 2 deduces it. You’d then have to make sure that same combo doesn’t allow Log 1 to deduce, because otherwise they would both deduce and wouldn’t fit the problem.

The poster above was using a sort of itemized table (well not quite, but essentially), tackling the problem systematically, which doesn’t surprise me coming from an engineer. Maybe try that sort of route.

Edit 2:
Originally Posted By mesobuild
Pretty obnoxious question.

I'll try without reading anything.

-

The combination must induce different conclusions from the two approaches.

Both knights:
All "no".
Both knaves:
yn, yn.
A knight, B knave:
y?, y?
A knave, B knight:
n?, y?

In case 4, the first logician knows B is a knight from the first answer. He can ask B if the other is a knave to deduce.
The second logician only knows at least one is a knave from the first answer. A knight would answer, "yes" while a knave might answer "yes" (if the other is a knight) or "no" (if the other is a knave). The second logician cannot deduce. His second question will be answered "yes", revealing only a mixed pair, which Knight/Knave and Knave/Knight both satisfy.

Answer: A is a knave, and B is a knight. I discovered this by inspecting the interesting looking answer set of the four cases.

Inspecting further, I think both logicians can deduce the answer from the other three cases.
I do not think the conclusion follows from that argument
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648572783 10-08-2021, 02:49 PM
-
#64
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Originally Posted By numberguy12
Not at all. This has nothing to do with the second question. What’s wrong with that first part? Knave A cant say no. As explained above.

Let’s try a different approach.

Can a knave ever say “2+2=4?”. Could he have ever said this in the past? Yes or no.
K Forget my reasoning on the first logician cause it doesn't even matter and I'm probably off on my reasoning there. Logician 2 is the one as I said before. Is he not? I only had 4 hours of sleep last night and I'm too tired and too lazy to go through log 1.
"Movin' ahead so life won't pass me by."
post 1648573643 10-08-2021, 03:08 PM
-
#65
  1. Savux
  2. Registered User
  1. Savux
  2. Registered User
  3. Join Date: Jun 2014
  4. Age: 37
  5. Posts: 2,671
  6. Rep Power: 18095
I think I have it

Logician A's questions cannot result in both inhabitants being a knave,

The second logicians questions can arrive at every conclusion,

The difference is, the second logicians questions have the ability to have them both be knaves, with certainty. Given the second logicians first question we will know for certain what inhabitant A is.

Inhabitant A answers yes
They then ask inhabitant B the second question and he says 'No'

Both Knaves,

Logician one cannot arrive at this conclusion
post 1648573953 10-08-2021, 03:16 PM
-
#66
  1. capowt
  2. cooked
  1. capowt
  2. cooked
  3. Join Date: Sep 2011
  4. Location: Sydney, NSW, Australia
  5. Posts: 10,836
  6. Rep Power: 226391
A is a KNIGHT
B is a KNAVE

LOG 1 Figured it out
post 1648575223 10-08-2021, 03:38 PM
-
#67
  1. mesobuild
  2. Premium User
  1. mesobuild
  2. Premium User
  3. Join Date: May 2020
  4. Posts: 17,953
  5. Rep Power: 44402
Originally Posted By numberguy12
I do not think the conclusion follows from that argument
The argument is inspection.

Knave/Knight

L1: "A, did B say you are a knave?" B did, so A lies and says, "No." L1 can conclude B is a knight because A only answers, "No," when B is a knight. L1 asks B, who L1 knows is a knight, if A is a knave. B answers truthfully, "Yes," proving to L1 A is a knave.
L1 now knows both identities.

L2: "A, did B say you are both knaves?" B did not, so A lies and says, "Yes." L2 can only eliminate the Knight/Knight solution from this answer. Asking either A or B if the other is a knave will result in an answer of "Yes," which occurs in the Knight/Knave solution AND the Knave/Knight solution. L2 cannot distinguish A and B but knows they are not Knave/Knave (because the knave would answer "No," to the second question if so.)
L2 knows Knave/Knight and Knight/Knave satisfy the "Yes, Yes" solutions but does not know which.
post 1648576503 10-08-2021, 03:53 PM
-
#68
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Inb4 the actual answer is my initial answer reworded.
"Movin' ahead so life won't pass me by."
post 1648582843 10-08-2021, 05:43 PM
-
#69
  1. Savux
  2. Registered User
  1. Savux
  2. Registered User
  3. Join Date: Jun 2014
  4. Age: 37
  5. Posts: 2,671
  6. Rep Power: 18095
Originally Posted By Spazzzzy
Just tried to teach myself truth table lmfao.

So it is testing:

p: A = Said im a Knave
q: B = Is other a Knave

we know p^q is inaccurate
we know p^`q is accurate
we know `p^q is accurate
we know `p^`q is accurate

Did B say you're a Knave, No. If second answer is repeated LOG1 knows both a Knight.

------------------------------------------------------------------------------------------------------------------
If B is a Knight:
B Said: Did B say you're a Knave, No. Is A a Knave Yes. Is B a Knave Yes. We know a lie has occurred.
B Didnt: Did B say you're a Knave, Yes. Is A a Knave Yes. Is B a Knave Yes. We know a lie has occurred.
------------------------------------------------------------------------------------------------------------------
If B is a Knave:
B Said: Did B say you're a Knave, Yes. Is A a Knave Yes. Is B a Knave Yes. We know a lie has occurred.
B Didnt: Did B say you're a Knave, No. Is A a Knave Yes. Is B a Knave Yes. We know a lie has occurred.
------------------------------------------------------------------------------------------------------------------
B said I'm a Knave, Yes. Is A a Knave No. Is B a Knave No - Not - Both Knaves

----------------------------------------------------------------------------------
p: A = Knave
q: B = Knight

p^q true
p^`q not true
`p^q not true
`p^`q true

Did B say you were Knaves, yes
Did B say you were Knaves, yes
Is other a Knave: Yes
Is other a Knave: Yes

--------------------------------------------------
Soz boyos just repeating same scenarios - don't know how to get around whether the statement was said or not.

I'll just say

Log1 figured it out
A is a Knave
B is a Knight
We don't need to know whether the statement is said or not. One of the logicians was able to come to a conclusion and the logicians also did not know whether it was actually said or not.

Question two is framed to provide you with certainty an answer regardless of whether it was actually asked or not.

Since we then know only one logician figured out the answer we have to consider what conclusion could be met by only one of the logicians.

In this case it is that both are knaves, determined by logician 2.

Logician 1 cannot make this conclusion
post 1648583793 10-08-2021, 05:57 PM
-
#70
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By Savux
We don't need to know whether the statement is said or not. One of the logicians was able to come to a conclusion and the logicians also did not know whether it was actually said or not.

Question two is framed to provide you with certainty an answer regardless of whether it was actually asked or not.

Since we then know only one logician figured out the answer we have to consider what conclusion could be met by only one of the logicians.

In this case it is that both are knaves, determined by logician 2.

Logician 1 cannot make this conclusion
Spazzzzy is right about this: if A and B are both Knaves, then the answer to Log 1’s Q’s are Yes, then No. This would enable Log 1 to deduce. Log 2 also could deduce based on the Yes, then No answer. Which doesn’t fit the problem.


Hmmm many Knave/knight Log 1 answers above. I do not agree with anyone’s proof on this though. I like the systematization though
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648584803 10-08-2021, 06:13 PM
-
#71
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Tables can help make these problems simpler, no nonsense. The very first row filled in. Note the inclusion of the middle column, after A and B. Can anyone fill the rest out. How many rows in the table for each logician.

∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648585763 10-08-2021, 06:33 PM
-
#72
  1. Savux
  2. Registered User
  1. Savux
  2. Registered User
  3. Join Date: Jun 2014
  4. Age: 37
  5. Posts: 2,671
  6. Rep Power: 18095
Originally Posted By Spazzzzy
Are you reading thread? Your answer is wrong

You can determine that it is 2 Knaves or 2 Knights, or Knight Knave easily in each solution. You cannot know if the claim has occurred in either scenario

OP has said it is unique solution only available in scenarios. We havent been able to determine which type holds position A and B thus far.
Tell me how you can deduce both as knaves from logician 1's questioning?

I might have fried my brain on this by now but I don't believe it is possible.
post 1648586183 10-08-2021, 06:42 PM
-
#73
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By Savux
Tell me how you can deduce both as knaves from logician 1's questioning?

I might have fried my brain on this by now but I don't believe it is possible.
A couple ways. One is just to fill out table 1 above.

In words though, Both knaves means the answers are "Yes", then "No" to logician 1. If logician 1 receives a "no" answer to the second question, it means that A and B are of the same type (knight/knight or knave/knave) (prove this to yourself if you have to). Log 1 can cross out the knight/knight possibility since the answer to the first was Yes (if it were knight/knight, that first answer would be no). Thus Log 1 knows it's knave knave with a "Yes","No" answer.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648589413 10-08-2021, 07:37 PM
-
#74
  1. Savux
  2. Registered User
  1. Savux
  2. Registered User
  3. Join Date: Jun 2014
  4. Age: 37
  5. Posts: 2,671
  6. Rep Power: 18095
Originally Posted By numberguy12
A couple ways. One is just to fill out table 1 above.

In words though, Both knaves means the answers are "Yes", then "No" to logician 1. If logician 1 receives a "no" answer to the second question, it means that A and B are of the same type (knight/knight or knave/knave) (prove this to yourself if you have to). Log 1 can cross out the knight/knight possibility since the answer to the first was Yes (if it were knight/knight, that first answer would be no). Thus Log 1 knows it's knave knave with a "Yes","No" answer.
Yeah I've overthought myself into mush.

I wanted to try to figure it out without writing it out in tables/excel sheet.

Going to just concede on this one and wait for result. I can accept that I am not intelligent enough to figure it out at this point.
post 1648589503 10-08-2021, 07:39 PM
-
#75
  1. Savux
  2. Registered User
  1. Savux
  2. Registered User
  3. Join Date: Jun 2014
  4. Age: 37
  5. Posts: 2,671
  6. Rep Power: 18095
Originally Posted By Spazzzzy
Knave cannot tell the truth so the Knave wouldn't ask the other Knave if they are a Knave.

Did B ask you if you're a Knave, the answer is no, but they lie and say yes.

Is the other person a Knave? No, no

Confirmed Knave.
Careful, the question isn't whether they asked the other if they are a knave, it is whether or not B claimed that A was a knave.
post 1648589523 10-08-2021, 07:40 PM
-
#76
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Logician 2 Discovered after only asking these questions

The second logician asked A whether B once claimed they were both knaves. Then he asked one of the two whether the other was a knave

AKnightNo BKnaveYes
AKnaveBKnightYes

So... I think Logician 2 has to have figured out that A is knight and B is Knave.

The Knight can't answer that the Knave has said they were both knaves cause even thoughAis a Knight and he would be lying there,Bwould technically be telling a half truth because he's a knave and knaves can't tell the truth. Then when asked the second question,Bresponds Yes,Ais a knave, lying.

I believe this is the only No/Yes combo Log 2 can come to. KnaveAcouldn't say No in the second example.

Maybe someone else has already answered this?
"Movin' ahead so life won't pass me by."
post 1648589993 10-08-2021, 07:50 PM
-
#77
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Edit: The rest of the combos have duplicate yes/yes, No/no, Yes/no, etc. ^^^^^^^
"Movin' ahead so life won't pass me by."
post 1648590023 10-08-2021, 07:51 PM
-
#78
  1. capowt
  2. cooked
  1. capowt
  2. cooked
  3. Join Date: Sep 2011
  4. Location: Sydney, NSW, Australia
  5. Posts: 10,836
  6. Rep Power: 226391
Ok I change my answer to:

A is a Knight
B is a Knave

Logician 2 figured it out

Log2 Q1: Has B claimed you're both Knaves?

Knight A: No, if true then A is a Knight and B is either a Knight or Knave. If a lie then A is a Knave, telling a lie and B HAS claimed they're both Knaves which is impossible for a Knight or a Knave to do. So the answer to Q1 is true making A a Knight.

Log2 Q2: "Is B a Knave?

Knight A: Yes, knowing A is a Knight we can deduce that this is true and B is a Knave.

Logician 1 Answers if KNIGHT/KNAVE:

Q1: YES
Q2 to A: YES

OR

Q1: YES
Q2 to B: YES

A KNAVE/KNIGHT would give the same answers.

Q1: YES
Q2 to A: YES

OR

Q1: YES
Q2 to B: YES
post 1648590193 10-08-2021, 07:55 PM
-
#79
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Originally Posted By capowt
Ok I change my answer to:

A is a Knight
B is a Knave

Logician 2 figured it out

Log2 Q1: Has B claimed you're both Knaves?

Knight A: No, if true then A is a Knight and B is either a Knight or Knave. If a lie then A is a Knave, telling a lie and B HAS claimed they're both Knaves which is impossible for a Knight or a Knave to do. So the answer to Q1 is true making A a Knight.

Log2 Q2: "Is B a Knave?

Knight A: Yes, knowing A is a Knight we can deduce that this is true and B is a Knave.

Logician 1 Answers if KNIGHT/KNAVE:

Q1: YES
Q2 to A: YES

OR

Q1: YES
Q2 to B: YES

A KNAVE/KNIGHT would give the same answers.

Q1: YES
Q2 to A: YES

OR

Q1: YES
Q2 to B: YES
Heueheuheu, beat ya by a bit
"Movin' ahead so life won't pass me by."
post 1648590273 10-08-2021, 07:56 PM
-
#80
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By Savux
Yeah I've overthought myself into mush.

I wanted to try to figure it out without writing it out in tables/excel sheet.

Going to just concede on this one and wait for result. I can accept that I am not intelligent enough to figure it out at this point.
Nah not about intelligence or anything like that. Some thoughtful posts being put out there by everyone ITT. Your point in the next post about being careful is correct.
Originally Posted By l2ambo
Logician 2 Discovered after only asking these questions

The second logician asked A whether B once claimed they were both knaves. Then he asked one of the two whether the other was a knave

AKnightNo BKnaveYes
AKnaveBKnightYes

So... I think Logician 2 has to have figured out that A is knight and B is Knave.

The Knight can't answer that the Knave has said they were both knaves cause even thoughAis a Knight and he would be lying there,Bwould technically be telling a half truth because he's a knave and knaves can't tell the truth. Then when asked the second question,Bresponds Yes,Ais a knave, lying.

I believe this is the only No/Yes combo Log 2 can come to. KnaveAcouldn't say No in the second example.

Maybe someone else has already answered this?
There's one problem with this type of solution. This problem cannot be answered by considering only one logician. It has to be shown that that one logician figures it out, but the other doesnt. Because remember, even if you could argue that some combination X,Y works for Logician 2 and allows him to deduce (and you have to rigorously show that combination allows him to deduce), anything could be going on with Logician 1. Also there are no half truths. A statement is either true or false.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648590373 10-08-2021, 07:59 PM
-
#81
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Originally Posted By numberguy12
Nah not about intelligence or anything like that. Some thoughtful posts being put out there by everyone ITT. Your point in the next post about being careful is correct.



There's one problem with this type of solution. This problem cannot be answered by considering only one logician. It has to be shown that that one logician figures it out, but the other doesnt. Because remember, even if you could argue that some combination X,Y works for Logician 2 and allows him to deduce (and you have to rigorously show that combination allows him to deduce), anything could be going on with Logician 1. Also there are no half truths. A statement is either true or false.
Then it's knave , knave. no/no Logician 2, Final answer. Log 1 can suck it.

This is the only combo in log 1 that doesn't have a duplicate
"Movin' ahead so life won't pass me by."
post 1648591233 10-08-2021, 08:20 PM
-
#82
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By capowt
Log2 Q1: Has B claimed you're both Knaves?

Knight A: No, if true then A is a Knight and B is either a Knight or Knave. If a lie then A is a Knave, telling a lie and B HAS claimed they're both Knaves which is impossible for a Knight or a Knave to do. So the answer to Q1 is true making A a Knight.
You're gonna have to walk me through exactly what you are trying to say here, it's worded confusingly. I wish you guys would just make the dang tables above lol

Also, you are claiming that Logician 1 Q1 answer if Knave/Knight is Yes, I claim it could possibly be No.

Let A be knave, B be knight. Suppose B once said "A is a knave" (very possible). Then when A is asked if B said that, A being the knave he is, would respond "No"
Originally Posted By Spazzzzy
Log 2

Knave A
Knight B

Did B state that you are both Knaves, NO.
Did A and B state the other is a Knave, YES

This will be my answer - assuming it is stating the simple fact of what B chose. Not the other persons interpretation of what B chose.

But you can also do the one we figured out before wherein KnaveKnave and KnightKnight can be figured out in each scenario.

The above is the only unique answer.

Cheers boyos this was fun srs.
If A was a knave, and B a knight, then B never would say they are both knaves. Thus A would respond "Yes" to "did B ever say you are both knaves.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648591593 10-08-2021, 08:25 PM
-
#83
  1. capowt
  2. cooked
  1. capowt
  2. cooked
  3. Join Date: Sep 2011
  4. Location: Sydney, NSW, Australia
  5. Posts: 10,836
  6. Rep Power: 226391
Originally Posted By Spazzzzy
Log 2

Knave A
Knight B

Did B state that you are both Knaves, NO.
Did A and B state the other is a Knave, YES

This will be my answer - assuming it is stating the simple fact of what B chose. Not the other persons interpretation of what B chose.

But you can also do the one we figured out before wherein KnaveKnave and KnightKnight can be figured out in each scenario.

The above is the only unique answer.

Cheers boyos this was fun srs.
So being a Knave, this is a lie which means B HAS claimed they are both Knaves.

A Knave can't claim another Knave is a Knave and a Knight can't claim himself as a Knave.

If A was a Knave he would answer YES to Q1. Which means B HASNT claimed both to be Knaves which means B is either a Knave or Knight

For B to be a Knight then A would have to answer YES to Q2 giving a YES/YES which is the same combo as a KNIGHT/KNAVE
post 1648591793 10-08-2021, 08:28 PM
-
#84
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
It's log 2AKnight/KnaveBNo/yes

It's the only thing left that makes sense with everything that has been said.

There is still the probability the The knave never claimed they were both knaves.
"Movin' ahead so life won't pass me by."
post 1648592093 10-08-2021, 08:35 PM
-
#85
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By l2ambo
It's log 2AKnight/KnaveBNo/yes

It's the only thing left that makes sense with everything that has been said.

There is still the probability the The knave never claimed they were both knaves.
Ah. And this is an important consideration that I think several glossed over in their answers. Although I think Spazzzzy made reference to it, and FarmerSon actually incorporated this into his analysis of Logician 1 correctly. Just because a Knight or Knave could have said something in the past, doesnt mean theydid.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648592213 10-08-2021, 08:37 PM
-
#86
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Originally Posted By numberguy12
Ah. And this is an important consideration that I think several glossed over in their answers. Although I think Spazzzzy made reference to it, and FarmerSon actually incorporated this into his analysis of Logician 1 correctly.
so who won? lol
"Movin' ahead so life won't pass me by."
post 1648592593 10-08-2021, 08:45 PM
-
#87
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
Originally Posted By numberguy12
Ah. And this is an important consideration that I think several glossed over in their answers. Although I think Spazzzzy made reference to it, and FarmerSon actually incorporated this into his analysis of Logician 1 correctly. Just because a Knight or Knave could have said something in the past, doesnt mean theydid.
I actually aluded to this 1 post before farmer

Knave A isn't bound to the answer of the second question so he can say anything he wants and still be lying in the eye's of the logician.
"Movin' ahead so life won't pass me by."
post 1648592663 10-08-2021, 08:47 PM
-
#88
  1. l2ambo
  2. Registered User
  1. l2ambo
  2. Registered User
  3. Join Date: May 2010
  4. Location: Canada
  5. Age: 36
  6. Posts: 8,380
  7. Rep Power: 8260
I'm takin the gold, GG everyone.
"Movin' ahead so life won't pass me by."
post 1648592773 10-08-2021, 08:51 PM
-
#89
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Originally Posted By Spazzzzy
Lol, so are we then doing a 50/50 for any of the above where Knave omitting and answer matters?
No, this is different than that point you were making before. That hasnt changed...."No","No" means it has to be Knight/Knight.

This is just that if Xcouldhave said something, doesnt mean X did. This possibility has to be considered in some of those Knave/Knight situations. But not in any Knight/Knight, or Knave/Knave situations.

Edit: ok you guys want the solution? It was basically said up there recently, but not completely argued for.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
post 1648593493 10-08-2021, 09:12 PM
-
#90
  1. numberguy12
  2. Registered User
  1. numberguy12
  2. Registered User
  3. Join Date: Jan 2017
  4. Posts: 6,938
  5. Rep Power: 51915
Basically you guys got there, gjdm. This one was pretty involved, and yes I realize some above gave the actual answer...just some nuances in there. It was fun guys, you are keeping me on my toes. I repped as many as I could.

Spoiler!

Logician 2 is the one who deduced

A is a Knight, B is a Knave.

Here is why:



-We discussed why neither Knave/Knave or Knight/Knight works. In either of those cases, both Logicians deduce because those answers are unique in their respective tables. So one of A,B is a knight, and one of A,B is a knave.

-If you look at rows 2 through 5 in Table 1....the Knight/Knave or Knave/Knight rows, the answers given will be either NO,YES or YES,YES. The problem is each of these are repeated, once under Kight-Knave, and once under Knave-Knight. So in no case can Logician 1 get responses and then deduce who is who. If YES,YES is said, could either be Knave/Knight or Knight/Knave. Same with NO/YES.

-So Logician 2 must have deduced. The only unique answer in rows 2-4 in Table 2 is NO,YES corresponding to A=Knight,B=Knave. Note that YES,YES could be either Kight/Knave, or Knave/Knight. Thus A is a knight and B is a knave.

I think the trick to this problem is realizing that you need 2 rows for some entries such as Knight/Knave in table 1. One with the dash where they didnt say it, and one with the check mark where they did say it.
∫∫ Mathematics crew ∑∑

♫1:2:3:4 Pythagoras crew ♫ ♫ 🧮

Nullius in verba
Quick Navigation Top Misc
Bookmarks
Digg.com
Digg
del.icio.us
del.icio.us
Stumbleupon.com
StumbleUpon
Google.com
Google
Facebook.com
Facebook
Posting Permissions
  1. You may not post new threads
  2. You may not post replies
  3. You may not post attachments
  4. You may not edit your posts