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Can someone explain this math bullchit to me?
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07-15-2022, 02:09 AM
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#1
- faketaxidriver
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- faketaxidriver
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Can someone explain this math bullchit to me?
Been studying for the entire day and this one's defeating me right now

How do I get to those values?

How do I get to those values?
07-15-2022, 02:26 AM
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#2
07-15-2022, 02:35 AM
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#3
07-15-2022, 02:41 AM
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#4
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Originally Posted By Jandels⏩
Triangulate the co-tangent of pi then fist yourself
Originally Posted By TokenV⏩
Timesabout 350
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07-15-2022, 02:42 AM
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#5
- faketaxidriver
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Originally Posted By PectoralBrah⏩
I'm doing that but it's only giving me the diagonal row from top left to bottom right, like this:Multiply the vertical rows in the first matrix by the horizontal rows in the second matrix, and add them

How do I get the whole matrix? This is probably something obvious, but I can't see it right now.
07-15-2022, 02:47 AM
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#6
- TappingTheZen
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- TappingTheZen
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Originally Posted By faketaxidriver⏩
multiply the horizontal of first, by vertical of the second to get the dot product..I'm doing that but it's only giving me the diagonal row from top left to bottom right, like this:

How do I get the whole matrix? This is probably something obvious, but I can't see it right now.

How do I get the whole matrix? This is probably something obvious, but I can't see it right now.
so the first row is:
(1,1,1,0).(1,1,1,0) = 1+1+1+0
(1,1,1,0).(1,2,1,1)= 1+2+1+0
(1,1,1,0).(1,1,0,2) = 1+1+0+0
(1,1,1,0).(0,1,2,1) = 0+1+2+0
row 2:
(1,2,1,1).(1,1,1,0) = 1+2+1+0
(1,2,1,1).(1,2,1,1) = 1+4+1+1
(1,2,1,1).(1,1,0,2) = 1+2+0+2
(1,2,1,1).(0,1,2,1) = 0+2+2+1
etc...
repeat the same with each row of the first matrix.
07-15-2022, 02:51 AM
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#7
- pyrogen
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y = mx + c will set you right m8
Pumpkin courtesy of BRANDERSS (https://forum.obnoxiousbrutes.com/showthread.php?t=180764903);
addendum courtesy of buttInspector (https://forum.obnoxiousbrutes.com/showthread.php?t=183054703).
P.S. Jandels needs a new sig m8s (Byzantine75 is a cheeky little bugger. srs.)
07-15-2022, 02:55 AM
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#8
- faketaxidriver
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Originally Posted By TappingTheZen⏩
oh yea I'm a retard. das it mane. repped.multiply the horizontal of first, by vertical of the second to get the dot product..
so the first row is:
(1,1,1,0).(1,1,1,0) = 1+1+1+0
(1,1,1,0).(1,2,1,1)= 1+2+1+0
(1,1,1,0).(1,1,0,2) = 1+1+0+0
(1,1,1,0).(0,1,2,1) = 0+1+2+0
row 2:
(1,2,1,1).(1,1,1,0) = 1+2+1+0
(1,2,1,1).(1,2,1,1) = 1+4+1+1
(1,2,1,1).(1,1,0,2) = 1+2+0+2
(1,2,1,1).(0,1,2,1) = 0+2+2+1
etc...
repeat the same with each row of the first matrix.
so the first row is:
(1,1,1,0).(1,1,1,0) = 1+1+1+0
(1,1,1,0).(1,2,1,1)= 1+2+1+0
(1,1,1,0).(1,1,0,2) = 1+1+0+0
(1,1,1,0).(0,1,2,1) = 0+1+2+0
row 2:
(1,2,1,1).(1,1,1,0) = 1+2+1+0
(1,2,1,1).(1,2,1,1) = 1+4+1+1
(1,2,1,1).(1,1,0,2) = 1+2+0+2
(1,2,1,1).(0,1,2,1) = 0+2+2+1
etc...
repeat the same with each row of the first matrix.
07-15-2022, 02:59 AM
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#9
- maori-rap
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- maori-rap
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Originally Posted By pyrogen⏩
It's all about the y=ax2 + bx + c...gotta get that parabola sortedy = mx + c will set you right m8
Cook the man some eggs!
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