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Forum » Misc IQ test (900+ IQ only)
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Thread: Misc IQ test (900+ IQ only)

post 1684393293 06-10-2023, 10:58 PM
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#31
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for i = 1 to 69350
for j = i+1 to 69350
for k = j+1 to 69350

if (i * j * k == 69350)
if (!list.ItemExists(i,j,k))
list.Add(i,j,k)

next k
next j
next i

return list
Nocrew crew

SS final perma ban request
https://forum.obnoxiousbrutes.com/showthread.php?t=184614323
post 1684393463 06-10-2023, 11:00 PM
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Originally Posted By BraddlesMcGee⏩
for i = 1 to 69350
for j = i+1 to 69350
for k = j+1 to 69350

if (i * j * k == 69350)
if (!list.ItemExists(i,j,k))
list.Add(i,j,k)

next k
next j
next i

return list
Edit: NM on closer look at ur code, it seems it should work.
post 1684393553 06-10-2023, 11:04 PM
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#33
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A mole is 6.02x10^23. I learned that in '83 and haven't used it since '85.
post 1684393603 06-10-2023, 11:05 PM
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Originally Posted By paulinkansas⏩
A mole is 6.02x10^23. I learned that in '83 and haven't used it since '85.
lol true
post 1684393613 06-10-2023, 11:06 PM
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OP claims 9th grade Indians can do this problem easily but clearly dying gay ones cannot
post 1684393623 06-10-2023, 11:06 PM
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#36
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Originally Posted By BraddlesMcGee⏩
1) 1, 2, 69347
Dude, product is multiplication, lmao..

you had the right idea, 1, 2 and 34,675
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post 1684393633 06-10-2023, 11:06 PM
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#37
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wincel please comment in my physics thread, quit playing with your little dinklet and get us off the planet
post 1684393693 06-10-2023, 11:07 PM
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#38
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Originally Posted By paulinkansas⏩
A mole is 6.02x10^23. I learned that in '83 and haven't used it since '85.
A blonde chick riding your 1100 cc motorcycle can't take a 90 degree turn with you on the back seat. I learned that in '93. We crashed into a building.
post 1684393793 06-10-2023, 11:10 PM
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Originally Posted By ErnieMccracken⏩
wincel please comment in my physics thread, quit playing with your little dinklet and get us off the planet
brah im in a dota game i will check later
post 1684393823 06-10-2023, 11:10 PM
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#40
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BRB, looking up "distinct integers".

Brb...
One party system; Most Republicans are Democrats, but no Democrats are Republicans.
Hayek and Mises were right; they're all socialists.
"To Call something fair or unfair is a subjective value judgment and not liable to any verification" Ludwig Von Mises
post 1684393953 06-10-2023, 11:13 PM
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#41
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69350 ÷ 2 = 34675
69350 ÷ 5 = 13870
69350 ÷ 10 = 6935
69350 ÷ 19 = 3650
69350 ÷ 25 = 2774
69350 ÷ 38 = 1825
69350 ÷ 50 = 1387
69350 ÷ 73 = 950
69350 ÷ 95 = 730
69350 ÷ 146 = 475
69350 ÷ 190 = 365
69350 ÷ 365 = 190
69350 ÷ 475 = 146
69350 ÷ 730 = 95
69350 ÷ 950 = 73
69350 ÷ 1387 = 50
69350 ÷ 1825 = 38
69350 ÷ 2774 = 25
69350 ÷ 3650 = 19
69350 ÷ 6935 = 10
69350 ÷ 13870 = 5
69350 ÷ 34675 = 2

But replace 69350 with 1 and ÷ and = with commas

Idk

Oh and remove the repeating half
post 1684394753 06-10-2023, 11:41 PM
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#42
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2 5 5 19 73

4 choose 2

6

wait forgot about ordering. combos of this like the other dude tried incorrectly.
post 1684394783 06-10-2023, 11:42 PM
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#43
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Originally Posted By unusefulidiot⏩
brah im in a dota game i will check later
Dota is for chubby incel asians
post 1684394853 06-10-2023, 11:44 PM
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#44
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15.

2 - 25 - 1387
2 - 95 - 365
2 - 475 - 73
2 - 19 - 1825
2 - 5 - 6935
5 - 10 - 1387
5 - 95 - 146
5 - 365 - 38
5 - 190 - 73
5 - 19 - 730
19 - 25 - 146
19 - 10 - 365
19 - 50 - 73
73 - 25 - 38
73 - 10 - 95
See you tomorrow
post 1684394893 06-10-2023, 11:46 PM
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Wincel put this in a job application will ya
post 1684395083 06-10-2023, 11:51 PM
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#46
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bump for high iq miscers
post 1684395293 06-10-2023, 11:56 PM
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#47
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Originally Posted By Pterodactyl314⏩
15.

2 - 25 - 1387
2 - 95 - 365
2 - 475 - 73
2 - 19 - 1825
2 - 5 - 6935
5 - 10 - 1387
5 - 95 - 146
5 - 365 - 38
5 - 190 - 73
5 - 19 - 730
19 - 25 - 146
19 - 10 - 365
19 - 50 - 73
73 - 25 - 38
73 - 10 - 95
Nope. There are more, such as 1 - 25 - 2774

You're probably going to get the full list soon tho...

But there is an easier way than listing them.
post 1684395353 06-10-2023, 11:58 PM
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#48
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Originally Posted By Pterodactyl314⏩
15.

2 - 25 - 1387
2 - 95 - 365
2 - 475 - 73
2 - 19 - 1825
2 - 5 - 6935
5 - 10 - 1387
5 - 95 - 146
5 - 365 - 38
5 - 190 - 73
5 - 19 - 730
19 - 25 - 146
19 - 10 - 365
19 - 50 - 73
73 - 25 - 38
73 - 10 - 95
This and my post?
post 1684395493 06-11-2023, 12:04 AM
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#49
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Originally Posted By Girthquake505⏩
This and my post?
Taking the top half of yours and combined with his, you have indeed listed all possibilities. However, this is not an acceptable solution. This is the brute force method lol.
post 1684395563 06-11-2023, 12:06 AM
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#50
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Originally Posted By unusefulidiot⏩
Taking the top half of yours and combined with his, you have indeed listed all possibilities. However, this is not an acceptable solution. This is the brute force method lol.
Damn, story of my life. I'm not a math guy, so in for the high iq solution.
post 1684395673 06-11-2023, 12:13 AM
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#51
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Originally Posted By Girthquake505⏩
Damn, story of my life. I'm not a math guy, so in for the high iq solution.
Ok well as u guys correctly listed, there are 26 ways to do this. First look at the prime factorization of 69350. It's 2*5^2*19*73. Let's first consider the number of ways we can allocate these prime factors without worrying about overcounting. The single power primes each can choose 1 of the 3 slots so we have 3^3 ways for that to happen. Next, we have 2 factors of 5 to put in 3 slots. We can use the stars and bars method and imagine listing 5 and 5 like this

55

but putting 2 dividers in to create 3 boxes

5||5 would correspond to (5,1,5) for example.

There are 2+3-1 (4 slots) choose 3-1 (2 places to put dividers) ways to do this, so 4 choose 2 which is 6.

So now we have 6*27 total ways without accounting for overcounting. First, recall the numbers must be distinct, so ways of the form (1,1, a) or (5,5, a) must be excluded. There are 3 ways for each of those so 6 total must be removed. Now we have 6*26 ways. But we calculated everything as if order mattered. Thus, we overcounted by a factor of 3!=6 ways. So, there are exactly 26 ways, as confirmed by your list.
post 1684395733 06-11-2023, 12:15 AM
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#52
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Originally Posted By unusefulidiot⏩
Ok well as u guys correctly listed, there are 26 ways to do this. First look at the prime factorization of 69350. It's 2*5^2*19*73. Let's first consider the number of ways we can allocate these prime factors without worrying about overcounting. The single power primes each can choose 1 of the 3 slots so we have 3^3 ways for that to happen. Next, we have 2 factors of 5 to put in 3 slots. We can use the stars and bars method and imagine listing 5 and 5 like this

55

but putting 2 dividers in to create 3 boxes

5||5 would correspond to (5,1,5) for example.

There are 2+3-1 choose 3-1 ways to do this, so 4 choose 2 which is 6.

So now we have 6*27 total ways without accounting for overcounting. First, recall the numbers must be distinct, so ways of the form (1,1, a) or (5,5, a) must be excluded. There are 3 ways for each of those so 6 total must be removed. Now we have 6*26 ways. But we calculated everything as if order mattered. Thus, we overcounted by 3!=6 ways. So, there are exactly 26 ways, as confirmed by your list.
Neat
post 1684396213 06-11-2023, 12:34 AM
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#53
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Originally Posted By unusefulidiot⏩
Nope. There are more, such as 1 - 25 - 2774

You're probably going to get the full list soon tho...

But there is an easier way than listing them.
Ok so 26

1 - 2 - 34675
1 - 5 - 13870
1 - 10 - 6935
1 - 19 - 3650
1 - 25 - 2774
1 - 38 - 1825
1 - 50 - 1387
1 - 95 - 730
1 - 190 - 365
1 - 475 - 146
1 - 950 - 73
2 - 19 - 1825
2 - 25 - 1387
2 - 95 - 365
2 - 475 - 73
2 - 5 - 6935
5 - 10 - 1387
5 - 19 - 730
5 - 95 - 146
5 - 190 - 73
5 - 365 - 38
19 - 10 - 365
19 - 25 - 146
19 - 50 - 73
73 - 10 - 95
73 - 25 - 38
See you tomorrow
post 1684396223 06-11-2023, 12:34 AM
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#54
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Originally Posted By Pterodactyl314⏩
Ok so 26

1 - 2 - 34675
1 - 5 - 13870
1 - 10 - 6935
1 - 19 - 3650
1 - 25 - 2774
1 - 38 - 1825
1 - 50 - 1387
1 - 95 - 730
1 - 190 - 365
1 - 475 - 146
1 - 950 - 73
2 - 19 - 1825
2 - 25 - 1387
2 - 95 - 365
2 - 475 - 73
2 - 5 - 6935
5 - 10 - 1387
5 - 19 - 730
5 - 95 - 146
5 - 190 - 73
5 - 365 - 38
19 - 10 - 365
19 - 25 - 146
19 - 50 - 73
73 - 10 - 95
73 - 25 - 38
yep

This was an example of a challenging stars and bars combinations problem for 8th-10th graders.

You guys got mogged by 9th grader ******
post 1684396333 06-11-2023, 12:36 AM
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#55
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Originally Posted By unusefulidiot⏩
Taking the top half of yours and combined with his, you have indeed listed all possibilities. However, this is not an acceptable solution. This is the brute force method lol.
Ha yeah I just factor tree’d 69350 and brute forced every combo

What took me 30 minutes could be coded in a nanosecond feelsbadman
See you tomorrow
post 1684396403 06-11-2023, 12:38 AM
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#56
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Originally Posted By Pterodactyl314⏩
Ha yeah I just factor tree’d 69350 and brute forced every combo
I could have given you a much uglier one though, and it would have been impractical to brute force.

I respect miscers who try tho. Life is about trying, not getting the answer. It's about trying to figure chit out.
post 1684396873 06-11-2023, 12:58 AM
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#57
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Originally Posted By unusefulidiot⏩
You guys got mogged by 9th grader Pajeet.
Damn
post 1684396933 06-11-2023, 01:02 AM
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#58
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Originally Posted By unusefulidiot⏩
Be careful...your list cares about order. And you haven't accounted for DISTINCT numbers...
his does care about distinct numbers. he does i, i+1, and i+2 guaranteeing that he will always have a distinct set.
post 1684397043 06-11-2023, 01:09 AM
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#59
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Originally Posted By outfoxxed⏩
his does care about distinct numbers. he does i, i+1, and i+2 guaranteeing that he will always have a distinct set.
I think he might have that double 5 set in there the way that's written? idk

Like 5, 5, 2774

Or maybe not because the other 2 values are always incremented?
post 1684397403 06-11-2023, 01:30 AM
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#60
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Originally Posted By Girthquake505⏩
I think he might have that double 5 set in there the way that's written? idk

Like 5, 5, 2774

Or maybe not because the other 2 values are always incremented?
Oh I see. Maybe it will work. I only looked at the code for a sec and assumed he was doing something different. His method should count them all.
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