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Forum » Can misc solve this math problem? Srs. IQ test
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Thread: Can misc solve this math problem? Srs. IQ test

post 1690851793 09-28-2023, 09:16 PM
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Can misc solve this math problem? Srs. IQ test

https://ibb.co/W03cTKc
post 1690851853 09-28-2023, 09:17 PM
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What does D/B equal?
post 1690852163 09-28-2023, 09:23 PM
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I'm gonna embarrass the crap out of myself, but 0.1621?

I didn't learn nearly enough math and just posting to find the answer
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post 1690852183 09-28-2023, 09:24 PM
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Depends, how long is the runway?
post 1690852223 09-28-2023, 09:25 PM
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i had two algebra classes in high school

no thanks Geoff
post 1690852313 09-28-2023, 09:26 PM
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Originally Posted By ZyraThornrise⏩
I'm gonna embarrass the crap out of myself, but 0.1621?

I didn't learn nearly enough math and just posting to find the answer
Nah
post 1690852363 09-28-2023, 09:27 PM
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.0226
post 1690852583 09-28-2023, 09:32 PM
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Originally Posted By MrPoopyPants⏩
.0226
Also nah
post 1690852963 09-28-2023, 09:40 PM
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Originally Posted By navid93⏩
Nah
I didn't think so

I'm figuring it as
A = 1.43 × BC = 1.87 × AD = 0.0605 × C
D = 0.0605 × (1.87 × (1.43 × B))
Which came to
D = 0.1620415 × B leaving me with that

Just trying to figure out where I'm overthinking
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post 1690853023 09-28-2023, 09:42 PM
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44.2?

let me try this again..
post 1690853083 09-28-2023, 09:44 PM
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Originally Posted By ZyraThornrise⏩
I didn't think so

I'm figuring it as
A = 1.43 × BC = 1.87 × AD = 0.0605 × C
D = 0.0605 × (1.87 × (1.43 × B))
Which came to
D = 0.1620415 × B leaving me with that

Just trying to figure out where I'm overthinking
Just set A and B to anything that will equal 1.43, I used A=143 and B=100 to make it easy

Since you have A now, for the second one 1.87=C/143. Find C by multiplying 143 and 1.87. Now you have C plug in C for the next one and continue the same step

Answer is .1618
post 1690853173 09-28-2023, 09:45 PM
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(D/C)(C/A)(A/B) = D/B

Notice how everything nicely cancels out.

In other words, just multiply the three numbers together
Physics crew
post 1690853183 09-28-2023, 09:45 PM
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Originally Posted By navid93⏩
Just set A and B to anything that will equal 1.43, I used A=143 and B=100 to make it easy

Since you have A now, for the second one 1.87=C/143. Find C by multiplying 143 and 1.87. Now you have C plug in C for the next one and continue the same step

Answer is .1618
goddamnit.
post 1690853253 09-28-2023, 09:47 PM
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Originally Posted By navid93⏩
Just set A and B to anything that will equal 1.43, I used A=143 and B=100 to make it easy

Since you have A now, for the second one 1.87=C/143. Find C by multiplying 143 and 1.87. Now you have C plug in C for the next one and continue the same step

Answer is .1618
Wouldn't that just find the approximation, though?
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post 1690853323 09-28-2023, 09:48 PM
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Originally Posted By GaloisTheory⏩
(D/C)(C/A)(A/B) = D/B

Notice how everything nicely cancels out.

In other words, just multiply the three numbers together
Fuark, i divided them instead of multiplying which is why my answer was incorrect.
post 1690853383 09-28-2023, 09:52 PM
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Originally Posted By GaloisTheory⏩
(D/C)(C/A)(A/B) = D/B

Notice how everything nicely cancels out.

In other words, just multiply the three numbers together
Thank you!
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post 1690853423 09-28-2023, 09:53 PM
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1.43/a = 1/b
.0605c = d

1.43x.0605c/a = d/b

c/a = 1.87

1.43x.0605x1.87 = d/b = 0.16178
Screw nature; my body will do what I DAMN WELL tell it to do!

The only dangerous thing about an exercise is the person doing it.

They had the technology to rebuild me. They made me better, stronger, faster......
post 1690854473 09-28-2023, 10:32 PM
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Post deleted by user
post 1690854563 09-28-2023, 10:35 PM
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bout 0.0350
post 1690854833 09-28-2023, 10:43 PM
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Originally Posted By ZyraThornrise⏩
I'm gonna embarrass the crap out of myself, but 0.1621?

I didn't learn nearly enough math and just posting to find the answer
[color=Deeppink] You can't cook, you can't do math.. This bitch is useless and you probably give the most apathic blow jobs.[color]
💋👨🏽‍🍳🇨🇴
AP4 Crew
post 1690855383 09-28-2023, 10:59 PM
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Misc mathematician is missed
post 1690857063 09-29-2023, 12:08 AM
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C = 1.87A

A = 1. 43B

D = 0.605C

D=0.605*1.87A

D=0.605*1.87*1.43B

Divide both sides by B

D/B = 0.605*1.43*1.87

Simple as finding the value of each variable in terms of another variable then substituting it into the equation
post 1690857273 09-29-2023, 12:17 AM
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Originally Posted By p7nk⏩
[color=Deeppink] You can't cook, you can't do math.. This bitch is useless and you probably give the most apathic blow jobs.[color]
Women don't need to know math. Only sloots think her ability to do math or earn money matters.
post 1690857393 09-29-2023, 12:23 AM
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Originally Posted By Voidgaze⏩
i had two algebra classes in high school

no thanks Geoff
I had Algebra 1, Geometry, and Algebra 2.





Fuk calculus or statistics
post 1690863713 09-29-2023, 05:28 AM
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Woke up and decided to solve this, very easy..


Ave Christus Rex

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post 1690864133 09-29-2023, 05:40 AM
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Originally Posted By CalmWind⏩
Woke up and decided to solve this, very easy..


no idea what you even did but it seems way too complex brah lol

- you have B as denominator in A/B (1.43)

- you have D as numerator in D/C (0.0605)

-> multiply these and you get AD/BC

- now all you need to do is take out A/C

- behold: you have C/A (1.87) as well

-> by multiplying all 3 you get the answer
++
post 1690864313 09-29-2023, 05:46 AM
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Originally Posted By TokenV⏩
no idea what you even did but it seems way too complex brah lol

- you have B as denominator in A/B (1.43)

- you have D as numerator in D/C (0.0605)

-> multiply these and you get AD/BC

- now all you need to do is take out A/C

- behold: you have C/A (1.87) as well

-> by multiplying all 3 you get the answer
complex???

i clearly showed my work, the logic is painfully easy to follow
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post 1690864443 09-29-2023, 05:53 AM
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post 1690864653 09-29-2023, 06:02 AM
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Originally Posted By CalmWind⏩
complex???

i clearly showed my work, the logic is painfully easy to follow

the fact you can't see it, and then offer "your" solution as LESS COMPLEX?? than mine??

you frauding, stop using chatgpt
relax brah, also lol @ "frauding" like it's impossible to know basic math smh

replacing an unknown by an arbitrary number and calling everything y is just a very confusing method

you also need to solve multiple equations while you really only need to multiply 3 numbers

I even did it in 2 steps to make it clear while it's really just 1 step

OP made this example specifically so it's easy to cancel everything out
++
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