Log In

Your email is not your username

Register

If you were a member of the old Bodybuilding.com forums and would like to reuse your previous username, you can request it below. We use your email only for registration and do not store it. For more information, please see our Privacy Policy.

Confirm your email

A registration code was sent to your email. Enter it here.

Welcome

You have successfully setup your account.

Sign in

Quick Navigation Bottom Misc
Forum
ยป High IQ math question
  1. Results 1 to 6 of 6
post 1627880163 01-08-2021, 03:14 AM
-
#1
  1. SnipeItLikePro
  2. Registered User
  1. SnipeItLikePro
  2. Registered User
  3. Join Date: Feb 2020
  4. Age: 56
  5. Posts: 1,039
  6. Rep Power: 4029

High IQ math question

https://ibb.co/SJKGS8S

In the diagram, KLJ is right angled at J, with JK=3 and JL=4.
KLJ is inscribed in a quarter circle with radius ML, as shown.

What is the area of the quarter circle?
post 1627880543 01-08-2021, 03:31 AM
-
#2
  1. 2am
  2. )))))))))))))))))))))))))
  1. 2am
  2. )))))))))))))))))))))))))
  3. Join Date: Jan 2013
  4. Posts: 21,153
  5. Rep Power: 196664
about 350/22.2816920329
No sig crew
post 1627880783 01-08-2021, 03:38 AM
-
#3
  1. littlecaesars59
  2. Banned
  1. littlecaesars59
  2. Banned
  3. Join Date: Dec 2019
  4. Age: 56
  5. Posts: 5,267
  6. Rep Power: 0
(lm^2*pie)/4
post 1627880973 01-08-2021, 03:50 AM
-
#4
  1. mesobuild
  2. Premium User
  1. mesobuild
  2. Premium User
  3. Join Date: May 2020
  4. Posts: 17,953
  5. Rep Power: 44402
5pi if K is the midpoint. I do not think it shows enough information if not.

proof:

3,4 sides of a right triangle --> AL = 5.

a, 2a, 5 right triangle --> 5a^2 = 25. a^2 = 5.

2a = 2sqrt(5).

Circle = pi*4*5 = 20 pi.
1/4 circle = 5 pi.

Other right angles can exist from simply adjusting J and K in the same vertical direction along their curves, so without K as a midpoint, so I do not think you can say much from dimensions of an inscribed right triangle alone without more information.
post 1627881443 01-08-2021, 04:11 AM
-
#5
  1. bfdehewdbyywhn
  2. Registered User
  1. bfdehewdbyywhn
  2. Registered User
  3. Join Date: Oct 2019
  4. Age: 56
  5. Posts: 47,380
  6. Rep Power: 103861
5.0000090449(pi)

or

[4.47214^2 (pi)]/4
HTC is too skinny for me. Fat Girls only crew. serious
Chubby Chaser and Fat Girls Only crew Founder
post 1627881713 01-08-2021, 04:21 AM
-
#6
  1. DoctorKazama
  2. Ph.D Broscience
  1. DoctorKazama
  2. Ph.D Broscience
  3. Join Date: Jul 2010
  4. Location: United States
  5. Posts: 17,312
  6. Rep Power: 41697
Teen misc ---------->
Quick Navigation Top Misc
Bookmarks
Digg.com
Digg
del.icio.us
del.icio.us
Stumbleupon.com
StumbleUpon
Google.com
Google
Facebook.com
Facebook
Posting Permissions
  1. You may not post new threads
  2. You may not post replies
  3. You may not post attachments
  4. You may not edit your posts