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Quick Navigation Bottom Misc
Forum » Can someone help me square this circle?
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Thread: Can someone help me square this circle?

post 1699299473 03-16-2024, 05:46 PM
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#1
  1. 401Delta
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  1. 401Delta
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Can someone help me square this circle?

---> ○
post 1699299513 03-16-2024, 05:47 PM
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#2
  1. Channel83
  2. Cable 12
  1. Channel83
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Originally Posted By 401Delta⏩
---> ○
[ ]
post 1699299523 03-16-2024, 05:48 PM
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#3
  1. uhohspaghetteos
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  1. uhohspaghetteos
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[○]
post 1699299643 03-16-2024, 05:50 PM
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#4
  1. 401Delta
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Originally Posted By Channel83⏩
[ ]
That's a channel, channel.
post 1699299713 03-16-2024, 05:52 PM
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#5
  1. Channel83
  2. Cable 12
  1. Channel83
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Originally Posted By uhohspaghetteos⏩
[○]
Then∣x+1−x2
​∣=2
​(2x2−1)∣cosα+sinα∣=2
​(2cos2α−1)
∣N2cos(α−π4)∣=N2cos(2α) α∈[0 ; π4]∪[3π4 ; π]∣N2
​cos(α−4π​)∣=N2
​cos(2α) α∈[0;4π​]∪[43π​;π]
1) α∈[0 ; π4]α∈[0;4π​]
cos(α−π4)=cos(2α)…cos(α−4π​)=cos(2α) …
2. α∈[3π4 ; π]α∈[43π​;π]
−cos(α−π4)=cos(2α)…−cos(α−4π​)=co s(2α)…

=

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